In triangle ABC, right-angled at B, if tan A = ଵ
√ଷ
, find the value of:
(i) sin A cos C + cos A sin C
(ii) cos A cos C – sin A sin C
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Step-by-step explanation:
GIVEN
tan A =1/√3
tan A =P/B
so P=1
B=√3
H=?
first we find H, by pyathagorus
P means perpendicular
B means base
H means hypotenus
in this question some are sin C and sin A and
some are cos C and cos A
so we solve it to see figure angle c and angle a
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