Question

In triangle ABC, right angled at B, if tanA=1/√3,find the value of :
1)sinA cosC + cosA sinC
2)cosA cosC - sinA sinC​

Answer 1

Step-by-step explanation:

tan A = 1/√3 therefore A= 30°

90+30+x= 180°

x= 60°

1) sinA cosC + Cos A sinC

= sin(A+C)

= sin(30+60)

= sin90

= 1

2)cosA cosC - sinA sinC

= cos(A+C)

= cos(30+60)

= cos90

= 0

Hope it helps you buddy

Answer 2

Answer:

Step-by-step explanation:

Given:

tanA=1/√3

A=30°

since B is right angle, C=60°

Now,

sinA.cosC + cosA.sinC

=sin(A+C)

=sin(30°+60°)

=sin90°

=1

cosA.cosC - sinA.sinC

=cos(A+C)

=cos(30°+60°)

=cos90°

=0

                                         I HOPE IT IS HELPFUL