Question

. In triangle ABC, right angled at B, sin A=3/5, then the value of cos C is *
5/4
4/5
3/5
5/3​

Answer 1

Sin A =3/5

let AC be hypotenuse

AC=5x. BC=3x

For Cos C base is BC and hypotenuse is AC

therefore Cos C= BC/AC

Cos C=3/5