Question

In triangle ABC, right angled at B.Write all trigonometric ratios from C.

Answer 1

Let's Consider Triangle ABC ;

Let 'A' be opposite side

Let 'B' be adjacent side

Let 'C' be hypotenuse .

$\mathcal \orange{possibilities \: of \: ratios : }$

$\frac{a}{c} = \frac{opposite}{hypoenuse} = \sin$

$\frac{b}{c} = \frac{adjacent}{hypotenuse} = \cos$

$\frac{a}{b} = \frac{ opposite}{adjacent} = \frac{ \sin( \theta) }{ \cos( \theta) } = \tan$

$\frac{c}{a} = \frac{hypotenuse}{opposite} = \frac{1}{ \sin( \theta) } = \cosec$

$\frac{c}{b} = \frac{hypotenuse}{adjacent} = \frac{1}{ \cos( \theta) } = \sec$

$\frac{a}{b} = \frac{ adjacent}{opposite} = \frac{1}{ \tan( \theta) } = \cot$