Math, asked by ekaragarg, 5 months ago

in triangle abc. right angled at C evaluate sin2A + sin2B + sin2C

Answers

Answered by vinitsarnaik04

0

Answer:

as sin2theta is 2sinthetacostheta so by this formula 2sin90cos90+2sin45cos45+2sin45cos45=0+1/2+1/2 =1 so final ans is 1

Answered by punit599119

0

Answer:

sin2A+sin2B+sin2C=180

sin2C=180-(sin2A+sin2B)

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