Question

In triangle ABC, Right angled at C, find cos A, tan A and cosec B if Sin A= 24/25 Please solve this as soon as possible and with the right answer 10th grade

Answer 1

Answer:

So here is your answer

Sin A =24/25

Sin A = perpendicular /hypotnuse

Therefor perpendicular =24 K and hypotnuse =25 k

So, using Pythagoras theorem

(24 K)² +(B) ²=(25 K)²

576 K²+(B)²=625k²

(B) ² =625k²-576k²

(B) ²=49k²

B=√49k²

B= 7k

Cos A = B/H

=7k/25k

=7/25

Tan A = P/B

=24k/7k

24/7

cosec A=H/P

=25k/24k

= 25/24