Question

in triangle abc right angled at C if tan a = 1 by root 3 show that sin a cos b minus cos a sin b = - 1 by 2​

Answer 1

Answer:

why does this question even exist

Answer 2

Answer:

Step-by-step explanation:

tan a =1/ root 3

constructing triangle of this

ac^2+bc^2=ab^2

1+3=ab^2

4=ab^2

ab=2

sin a = 1/2

cos b= 1/2

cos a =root 3 /2

sin b =root 3 /2

therefore

sinacosb-cosasinb

1/4-3/4

-2/4

-1/2