in triangle abc right angled at C if tan a = 1 by root 3 show that sin a cos b minus cos a sin b = - 1 by 2
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Step-by-step explanation:
tan a =1/ root 3
constructing triangle of this
ac^2+bc^2=ab^2
1+3=ab^2
4=ab^2
ab=2
sin a = 1/2
cos b= 1/2
cos a =root 3 /2
sin b =root 3 /2
therefore
sinacosb-cosasinb
1/4-3/4
-2/4
-1/2
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