In triangle abc right angled ath c find the value of sec(a+b)
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Answer:
angle c equals to right angle so sum of rest angle nis also right angle
and sec 90 degree equal to 1
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C = 90
Answer:
A+B+C = 180
A+B+90= 180
A+B= 180-90
A+B=90
sec(a+b)
sec(90)............(a+b=90)
sec90=1/cos90.................cos90=0
sec90=1/0
Therefore...
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