Question

IN triangle ABC seg AC PERPENDICULAR SEG BC ANGEL C=45°, BD=5 AND AC =
$8 \sqrt{5}$
then find ad and bc.

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Answer 1

Answer:

AD = 8 and BC = 13

Step-by-step explanation:

given AD is perpendicular to BC

=> ∠D = 90°

now consider Δle ADC

here ∠D is 90° and ∠C is 45°

sum of angles equals to 180° so, ∠A = 45°

when two angles are equal it is a isosceles triangle

in which two sides are also equal

so AD = DC

hypotenuse theorem, AC² = DC² + AD²

=> (8√2)² = 2DC²

=> 128/2 = DC²

=> DC = 8 =AD

so AD = 8 then

BC = BD + DC

=> BC = 13