Question

In triangle ABC,seg AP perpendicular side BC,seg BQ perpendicular side AC ,B-P-C,A-Q-C then show that triangle CPA similar Triangle CQB.if AP=7 BA=8 BC=12 then find AC​

Answer 1

Answer:

15.12cm

Step-by-step explanation:

proof

in ∆ cpa & cqb,

< ACP = < QCB

< APC = < BQC =90°

so by aa similarity criteria, ∆ CPA~∆ CQB

bp^2= (8*8) - (7*7)

bp=√64-49

bp=√15

pc=12-√15

ac=√(7*7)+(12-√15)^2

=√49+8.12

=15.12

Answer 2

Answer:

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