in TRIANGLE ABC ,seg DE parallel to side BC such that DB is 1.5 cm , AD is 3cm ,CE is 1cm find A
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Answer:
By using basic proportionality theorem,
AD/DB = AE/EC
1.5/3 = 1/x
3/1.5 = x
x = EC = 2
AC = AE + EC = 1 + 2 = 3 cm.
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