Math, asked by shreyasasware, 3 months ago

in TRIANGLE ABC ,seg DE parallel to side BC such that DB is 1.5 cm , AD is 3cm ,CE is 1cm find A

Answers

Answered by aswin8935
1

Answer:

By using basic proportionality theorem,

AD/DB = AE/EC

1.5/3 = 1/x

3/1.5 = x

x = EC = 2

AC = AE + EC = 1 + 2 = 3 cm.

Step-by-step explanation:

hope it helps you

mark me as brilliant

Similar questions