In triangle ABC, seg DE || side AB, such that AD= 2DC. If A(□ABED)=56 sq. units then find A(triangle ABC)
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ab = 2 dc (given)
Since area is proportional to square of side;
Hence,
Area of ∆ ABC = 4 x Area of ACED
But Area of ACED = 56 (given)
=> Area of ∆ ABC = 4 x 56 = 224
So area of ∆ ABC is 224 sq. units.
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Answered by
2
Answer:
ab = 2 dc (given)
Since area is proportional to square of side;
Hence,
Area of A ABC = 4 x Area of ACED
LTE LTE1 4+ Ill 53%
29
4.0
But Area of ACED = 56 (given)
=> Area of A ABC = 4 x 56 = 224
So area of A ABC is 224 sq. units.
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