Question

in triangle ABC , seg DE || side BC such that A-D-C and A-E-B. if AD =2CD and A (quadrilateral BCDE ) = 40 sq.cm then find A (TRIANGLE ABC)

Answer 1

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Answer 2

Answer:

ab = 2 dc (given)

Since area is proportional to square of side;

Hence,

Area of ∆ ABC = 4 x Area of ACED

But Area of ACED = 56 (given)

=> Area of ∆ ABC = 4 x 56 = 224

So area of ∆ ABC is 224 sq. units.

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Step-by-step explanation:

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