in triangle ABC , seg DE || side BC such that A-D-C and A-E-B. if AD =2CD and A (quadrilateral BCDE ) = 40 sq.cm then find A (TRIANGLE ABC)
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Answer:
ab = 2 dc (given)
Since area is proportional to square of side;
Hence,
Area of ∆ ABC = 4 x Area of ACED
But Area of ACED = 56 (given)
=> Area of ∆ ABC = 4 x 56 = 224
So area of ∆ ABC is 224 sq. units.
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