Question

In triangle abc seg MN is parallel to side AC seg MN divides triangle ABC into two parts equal in area determine AM. upon MB

Answer 1

Answer: Just change the value u will get answer

Answer:

Step-by-step explanation:

in ΔABC and ΔAMN

segment MN ║ BC

∠AMN=∠ABC (corresponding angle)

∠ANM=∠ACB (corresponding angle)

∠A si common

so ΔABC≅ΔAMN (CPCT)

given that 2*(area of ΔAMN )= area of ΔABC

so

\frac{AM}{MB}=\sqrt{\frac{area of ABC}{area of AMN}}\\\\\frac{AM}{MB}=\sqrt{\frac{2}{1}}\\\\\frac{AM}{MB}=\sqrt{2}