Question

in triangle ABC seg MN is parallel to side bc then prove that triangle ABC is similar to triangle amn by sas test​

Answer 1

Step-by-step explanation:

in ∆ABC and ∆AMN

1. angleA =angleA(common)
2. angleB=angleM(corresponding angle)
3. angleC=angleN(corresponding angle)

therefore,∆ABC similar to ∆AMN by AAA similarity

Answer 2

Step-by-step explanation:

I hope it will

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