Question

In triangle ABC,seg MN parallel to seg BC If BM=6,AN=5,AM=2,then find NC

Answer 1

Answer:

since MN II TO BC  

AM/MB=AN/NC........ BASIC PROPORTIONALITY THEOREM)

2/6=5/X

X=30/2

X=15

Answer 2

Since MN:BC

AM/MB= AN/NC

2/6=5x

x=30/2

x=15