Question

in triangle abc seg xy parallel bc. if m and n are the midpoints of aeg ay and ac respectively. prove that
1st triangle axm similar triangle abn
2nd seg xm parallel seg bn​

Answer 1

Answer:

Given: In triangle PQR,  XY || QR ,M and N are midpoints of  PY and PR .

∴ PM=MY= MN

and PY=YR

∴PY=2PM

and YR=2PM=2MN

Therefore by basic proportionality theorem we have ,

\begin{gathered}\dfrac{PX}{XQ}=\dfrac{PY}{YR}\\\\\Rightarrow\dfrac{PX}{XQ}=\dfrac{2PM}{2MN}\end{gathered}XQPX=YRPY⇒XQPX=2MN2PM []