In Triangle ABC Segment PQ Parallel to Segment BC, If AP is 2.4, PQ is 2 and PB is 7.2, then find QC.
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Step-by-step explanation:
In ∆APQ
AP+PQ+AQ=180
2.4+2+AQ=180
4.4+AQ=180
AQ=180-4.4
AQ=26
By BPT
AP/PB=AQ/QC
2.4/7.2=26/QC
2.4=26*7.2
78=QC
gautamsimran:
180-44/10
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