Question

In triangle ABC show that cos²B -cos²C/b+c +cos²C-cos²A/a+c = cos²A-cos²B/a+b

plz help me for this ​

Answer 1

a^2(cos^2b-cos^2c)+b^2(cos ^c-cos^2a)+c^2(cos^2a-cos^2b)=0 a²(cos2B- cos2C)+b²(cos2C-cos2A)+c²(cos2A-cos2B)=0

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