Question

In triangle ABC, show that sin square A/2 + sin square B+C/2=1​

Answer 1

Step-by-step explanation:

A+B+C= 180

A= 180-(B+C)

on dividing both side by 2

A/2= {180-(B+C)}/2

A/2= 90-(B+C)/2

on multiply both side by sin²

sin²A/2= sin²{90-(B+C)/2}

sin²A/2= cos²(B+C)/2

sin²A/2= 1-sin²(B+C)/2

sin²A/2+sin²(B+C)/2= 1

Hence LHS=RHS proved.

#666

Answer 2

Answer:

this is the answer hope its helpful