Math, asked by disharajatb, 11 months ago

In triangle ABC
side AD perpendicular to BC
then, prove that

AB²+CD² = BD² + ACsquare

Answers

Answered by spandan306

1

Step-by-step explanation:

AD2=AB2-BD2

AD2=AC2-DC2

AB2-BD2=AC2-DC2

AB2+CD2=BD2+AC2

Hence proved

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