Question

In triangle ABC side BC has been produced to point D such that Angle ACD=120° If Angle B=1/2 of angle A then angle A=??​

Answer 1

Answer:

Angle A = 80°

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Answer 2

Answer:

The measure of ∠A is 80°.

Step-by-step explanation:

Given:-

In ΔABC, the side BC is produced to point D such that ∠ACD = 120°. Also, ∠B = 1/2∠A.

To find:-

The measure of ∠A.

From the figure,

Using the exterior angle property - "The exterior angle is equal to the sum of the two opposite interior angles."

∠A + ∠B = ∠ACD

Since it is given that ∠ACD = 120° and ∠B = 1/2∠A. So,

∠A + 1/2∠A = 120°

       3/2∠A = 120°

             ∠A = 120 × 2/3

             ∠A = 40 × 2

             ∠A = 80°

Therefore, the measure of ∠A is 80°.

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