Question

In triangle ABC side BC is greater than side AB by 3 but less than AC by 2 perimeter os 53 find gretest side of triangle

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

BC=AB +3 (1)

AB+BC+CA=53

BC=AC-2 (2)

Now, AB+3=AC-2

3+2=AC-AB

5=AC-AB

AB=AC-5

AC-5+AC-2+AC=53

AC+AC+AC-5-2=53

3AC=53+7

3AC=60

AC=60/3

AC=20/answer...