Question

in triangle ABC sin A+B/2= cos c/2​

Answer 1

$heya \\ here \: is \: ur \: answer \: with \: eplanation$

$\sin (a + b \div 2) = \cos \: c + 2$

A+B+C=180°[The sum of a triangle is 180]

A+B=180-C

A+B/2=180-C/2

=>180÷2-C/2

=>(90-C/2)

Substitution,

sin(90-C/2)

Since,

sin(90-A)=cos A

cos C/2

LHS=RHS