Question

In triangle ABC sin(a+b)-c

Answer 1

in triangle ABC
<A+<B+<C = 180°
<A+ <B = 180°-<C

TAKING GIVEN EQUATION...


sin(A+B)-sinC
=sin(180-C) - sinC
= sin (180-C-C)
= sin (180-2C)
= sin (2C)

Answer 2

$- \sin(a + b) - c \\ = \sin(180 - c) - c \\ = \sin(180 - 2c) \\ = \sin(2c )$

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