In triangle abc sin(b+c-a)=1=cos(c+a-b)find the value of a,b,c
Answers
Answered by
3
gives that a+b+c=180
also c+a-b=0
on solving
c+a=b
b=90
luckyjoshi615:
THAT IS actually b=45
-a+b+c=90
so c+a =45
Similar questions