in triangle abc, sinB/sin(A+B) is equal to
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Heya user,
In a triangle, ∠A + ∠B + ∠C = 180°
=> ∠A + ∠B = 180° - ∠C
Now, sin B / sin ( A + B ) = sin B / sin ( 180 - C ) = sin B / sin C
By sine rule, b / sin B = c / sin C => sin B / sin C = b / c;
In a triangle, ∠A + ∠B + ∠C = 180°
=> ∠A + ∠B = 180° - ∠C
Now, sin B / sin ( A + B ) = sin B / sin ( 180 - C ) = sin B / sin C
By sine rule, b / sin B = c / sin C => sin B / sin C = b / c;
kka:
thanks
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