In triangle ABC. tan( A-B-C)=
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Answered by
2
Answer:
45°hope it helps you mate
Answered by
1
Explanation:
A+B+C=180 so that
B+C=180-A
A-B-C=A-(B+C)=A-(180-A)=2A-180
tan(x-y)=(tanx-tany)/(1+tanxtany)
Therefore ,tan(2A-180)=(tan2A-tan(180))/(1+tan2Atan(180))
=tan2A/1-tan2A)
since tan(180)=-1
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