Question

in triangle ABC tanA+tanB+tanC=6 and tanA tanB=6 find this eq. are which triangle

Answer 1

A+B+C=180


A+B=180-C


Tan(A+B)=-TanC


(TanA+TanB)/(1-TanATanB)=-TanC


TanA+TanB+TanC=TanATanBTanC=6


TanC=1. so the angle C is acute.


TanA+TanB=5


TanA-TanB=1


therefore TanA=3 and TanB=2


A and B are also acute.