Question

In triangle abc the angle bisectors of interior angle b and exterior angle c meet at o if angle a 70 find angle boc

Answer 1

Answer:

125°

Step-by-step explanation:

∠a=70°

Let ∠b=2x

Then ∠c= 180°-70°-2x

∠c=110°-2x

∠obc=∠b/2=x

∠ocb=∠c/2=55°-x

in Δboc,

x+55°-x + ∠boc = 180°

∠boc=180°-55°

        =125°