in triangle abc the bisector ad of angle a is perpendicular ro side bc show that triangle abc is an isosceles triangle'
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In ΔADB & ΔADC,
(i) ∠BAD=∠CAD(∵AD is the angular bisector of ∠A)
(ii) AD is the common side
(iii) ∠ADB=∠ADC (Given, AD is perpendicular on BC)
∴ ΔADB is congruent to ΔADC
∴AB=AC
∴ΔABC is an isoscales triangle.
(i) ∠BAD=∠CAD(∵AD is the angular bisector of ∠A)
(ii) AD is the common side
(iii) ∠ADB=∠ADC (Given, AD is perpendicular on BC)
∴ ΔADB is congruent to ΔADC
∴AB=AC
∴ΔABC is an isoscales triangle.
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