Question

in triangle abc the bisector of angle A is perpendicular to side BC see the figure given prove that AB is equal to AC and triangle ABC is isosceles​

Answer 1

Step-by-step explanation:

in∆ABD and∆ACD

angle BAD= angleCAD(given)

AD=AD(common)

angle BDA= angleCDA(AD is perpendicular to BC)

therefore

∆ABD~= ∆ACD(by ASA congurence)

AB=AC(by CPCT)

we know that the triangle is isosceles triangle if two sides are equal and here AB equal to AC therefore it is an isosceles triangle please mark this answer as brainliest

Answer 2

Answer:

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