Question

in triangle abc the bisector of angle A meets BC at the line PQ is parallel to AC meets ab BC and BD at pqr respectively show that PR into bq is equal to QR into BP II a b into C Q is equal to BC into ap​

Answer 1

Step-by-step explanation:

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BP/BQ  = PR/PQ -- (equation 1)

AB/BC = AD/DC -- (equation 2)

PQ||AC So ΔBPQ ≈ ΔBAC

BP/BA = BQ/BC

BP/BQ = AB/BC --- (equation 3)

so from the equation 1 and equation 2 we can get this:

PR/RQ = AD/DC

Answer 2

Answer:

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