Question

in triangle abc the bisector of Angle b and angle c intersect each other at o. prove that angle BOC is equal to 90° + 1/2 angle a.​

Answer 1

Answer:

Proof:

In triangle ABC,

A+B+C=180°[angle sum property]

B+C=180°-A

÷by 2,(since BO & CO bisects B & C)

B + C = 90°- A

2. 2 2

In triangle BOC,

B + C + BOC = 180°

2. 2

90°-A + BOC = 180°

2

BOC = 180°-90° +A

2

BOC=90°+1 (A)

2

Hence proved