In triangle abc, the bisector of angle b and angle c meet at point o within the triangle. if angle boc is equal to 148 degree, then the measure of angle a is
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Answer:
116°
Explanation:
in triangle boc
<obc =1/2 b
<ocb =1/2 c
<boc = 148°
1/2 b +1/2 c +148°= 180°
1/2 b + c = 180 °-148°
1/2 b+c = 32
b+c = 32 ×2
= 64
a + b +c = 180°
a + 64 =180
a =180 -64
a = 116
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Given :
The measure of ∠ boc = 148°
where , o is point where bisector of angle b and angle c meet .
To find :
The measure of angle a .
Solution :
The measure of ∠ boc = 148°
In a triangle , sum of all angles are equal to 180° .
In Δ boc ,
[ ( ∠ b + ∠ c ) / 2 ] + ∠ boc = 180°
→ [ ( ∠ b + ∠ c ) / 2 ] + 148° = 180°
→ ( ∠ b + ∠ c ) / 2 = 32°
→ ∠ b + ∠ c = 64°
then , in Δabc ,
∠ a + ∠ b + ∠ c = 180°
→ ∠a + 64° = 180°
→ ∠a = 116°
The measure of angle a = 116°
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