Question

)
In
triangle ABC, the bisector
of angleA meets BC
in D. Show that AD is less than
Gm
of AB and AC​

Answer 1

Answer:

In^DAM, DE BISECTS <ADB

DA/DB = AE/EM _ _ (1)

IN DAC , DF BISECTS <ADC

DA / DC= AF/FC

DA/ DM = AF/ FC _ _ _ (2)

FROM 1 AND 2 WE WILL GET AE/ EB= AF/ FC

IN ABC

EF BC