Question

In triangle abc,the bisector of <B and<C intersect each other at a. point d .If <BDC=104°,then the measure of<A is​

Answer 1

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ABC is a triangle, the bisector of the exterior angle and B and C intersect each other at D. Prove angle D is half of angle A?

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Step-by-step explanation:

A+B+C = 180° => A/2 + B/2 + C/2 = 90°

=> B/2+C/2 = 90°-A/2 …….………(1).

In the ∆ BCD, (B/2) + (C+90°-C/2) + 60° = 180°

=> B/2 + C/2 = 30° = 90°- A/2 = 30° => A = 120°

Answer 2

Answer:

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