Question

In triangle abc the bisectors of angle abc and angle bca intersect at each other at point 0 if angle boc = 100 degree find angle a

Answer 1

the answer is 20 degrees

Answer 2

Answer:

a=20°

Step-by-step explanation:

Angle B + angle b is equal to 180 degree linear pair 800 degree + angle b is equal to 180 degree implies that body is equal to 180 - 100 degree and Angle b is equal to 80 degree angle b o d x h a exterior angle to anger to triangle abc angle b o d is equal to angle abc + angle ACB implies that 80 degrees equal to angle abc + angle ACB now OB and OC is the bisector of angle abc and angle ACB then angle abc + angle ACB is equal to 2 whole angle abc + angle b is equal to 2 into 80 is equal to one sixty degree now in in triangle abc angle A + Angle B + angle C is equal to 180 degree angle sum property angle A + 60 degree is equal to 180 degree angle A is equal to 180 degree minus 160 degree and Angle is equal to 20 degree