Question

in triangle abc the external bisectors of angle abc and angle acb meets at o if angle boc is equal to 45 degree then angle BAC is​

Answer 1

Answer:

Step-by-step explanation:

In △ABC,

∠ABC+∠ACB+∠BAC=180

∠ABC+70+50=180

∠ABC=60  ∘

 ∠OCB=  2 1

​(180−∠ACB)

∠OCB=  2 1

​ (180−50)

∠OCB=65  ∘

∠OBC=  2 1

(180−∠ABC)

∠OBC=  2 1

(180−60)

∠OBC=60  ∘

In △OBC, ∠OCB+∠OBC+∠BOC=180

65+60+∠BOC=180

∠BOC=180−125

∴∠BOC=55  

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