In triangle ABC, the length of BC is less than twice the length of AB by 3 cm. The length of AC exceeds the length of AB by 9 cm. The perimeter of triangle is 34 cm. The length (in cm) of the smallest side of the triangle is:
Answers
The shortest length is 7 cm.
Step-by-step explanation:
BC = 2 AB - 3 ----(1)
AC = AB + 9 ----(2)
AC + BC + AB = 34 ----(3)
Putting value of BC and AC in equation (3).
2AB - 3 + AB + 9 + AB = 34
4 AB + 6 = 344 AB = 34 - 6
AB = 28 / 4 = 7 cm
Putting value of AB in equation (1) and (2)
BC = 2 (7) - 3 AC = 7 + 9
BC = 14 - 3 AC = 16
BC = 11 AC = 16
Hence the shortest length is 7 cm.
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The sides of a triangle are 5 cm; 7 cm and 10 cm. find the length of the median to the longest side. ?
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Answer:
The shortest length is 7 cm.
Step-by-step explanation:
BC = 2 AB - 3 ----(1)
AC = AB + 9 ----(2)
AC + BC + AB = 34 ----(3)
Putting the value of BC and AC in equation (3).
2AB - 3 + AB + 9 + AB = 34
4 AB + 6 = 344 AB = 34 - 6
AB = 28 / 4 = 7 cm
Putting the value of AB in equation (1) and (2)
BC = 2 (7) - 3 AC = 7 + 9
BC = 14 - 3 AC = 16
BC = 11 AC = 16
Hence the shortest length is 7 cm.
And, If you want to help please give the answer to this following question from the given link:
https://brainly.in/question/28248483
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