in triangle abc the length of sides BC, CA and AB are a, b and c respectively.Median AD drawn from A is perpendicular to BC then b is
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Given:
In Triangle ABC
Length of BC = a
Length of CA = b
Length of AB = c
AD ⊥ BC
To Find:
Value of b
Solution:
According to the properties of triangle
b² = a² + c² - 2ac . 2c/x
b² = a² + c² - 4c²
b² = a² - 3c²
Therefore,
b = √a² - 3c²
Answer: The value of b is √ a² - 3c²
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