In triangle ABC, the line BD is perpendicular to AC.
AD = (x + 6) cm, DC = (x + 2) cm and the height BD = (x + 1) cm.
(i) Find area of triangle in term of "X"
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S = A+B+C by 2
= (x+6)+(x+2)+(x+1) by 2
=3x+ 9 by 2
Area= √{s(s-a)(s-b)(s-c)},
√{3x + 9 by 2 (3x+9 by 2 -( x+6))(3x+9 by 2 (- x+2))(3x+9 by 2 -(x+1))
√{3x + 9 by 2 ( x+3 by 2 ) (x+5 by 2 ) ( x+6 by 2 )
√{ 2 ( 3x + 9 ) (2(x + 3 )) (2(x+5)) (2(x+6))
√{ (6x + 18 ) (2x - 6 ) (2x + 10) ( 2x + 12 )
√{4x + 102
2x + 51
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