In triangle abc the measure of a is equal to the sum of the measure of angle b and angle C also the ratio of measure of Angle B an Embassy is 4 ratio 5 then find the measure of angle of triangle
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Please do correction in question as following:
The angle A of a triangle ABC is equal to the sum of other two angles.Also ,the ratio of the angle B to the angle C is 4:5. find the measure of each angle
Step-by-step explanation:
Let ∠A=a,∠B=b,∠C=c
a=b+c
2a=a+b+c=180
2a=180
a=90
90=b+c
b=90-c
now b/c=5/4
so 90-c/c=4/5
5*(90-c)=4c
450-5c=4c
9c=450
c=50
b=180-(90+50)=40
∠A=90 , ∠B=40 and ∠C=50
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