Question

in triangle abc the measure of angle A is equal to the sum of measure of Angle B and angle C also the ratio of measures of Angle B and angle C is 4 is to 5 then find the measures of angle of triangle ​

Answer 1

Answer:

Angle A= B + C

angle B:angle C = 4x : 5x

angle A = 4x + 5x =9x

angle A + B+ C = 180

9x+9x=180

18x=180

X= 10

angle A = 90

B= 40

C= 50

Answer 2

Answer:

∠A= 90°

∠B= 40°

∠C= 50°

Step-by-step explanation:

Given:

∠B+∠C= ∠A

∠B:∠C= 4:5

To find:

Measure of all angles

Solution:

Let m∠B= 4x

      m∠C=5x

Since ∠A=∠B+∠C

Therefore, ∠A= 4x + 5x

                       = 9x

Also, since measure of all angles of a triangle sum up to 180°

Therefore, ∠A+∠B+∠C=180°

                9x + 4x + 5x= 180

                18x=180

                x= 180/18

                x=10°

Since x=10°

Therefore ∠A=9x=9×10= 90°

                 ∠B=4x=4×10=40°

                 ∠C=5x=5×10=50°

<Woah that took me a lot of time to type down! Hope this helps:)>