Question

in triangle ABC the measure of Angle B is 5 degree less than the thrice of the measure of Angle A . Angle C is 15 degree more than measure of angle B . find the measure of each angle of ∆ABC​

Answer 1

Let the masuer of angle A = X

and the masure of angle B = 3X-5

and the masure of angle C = angle B + 15

= 3X-5+15

= 3X+10

Now,

angle A + angle B + angle C = 180

X + 3X -15 + 3X + 10 = 180

4X + 3X -15 +10 = 180

7X -5 = 180

7X = 180-5

X = 175 / 7

X = 25

so,

angle A = 25

angle B = 3X-5

= 3×25 - 5

= 75 -5

= 70

angle C = 3X +10

= 3×25 +10

= 75 +10

= 85

Hope it will help you

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Answer 2

Answer:

Angle A=25°; Angle B=70°; Angle C=85° .

Step-by-step explanation:

B=3A-5

C=B+15

C=3A-5+15

C=3A+10

A+3A-5+3A+10=180

7A+5=180

7A=175

A=25°

B=70°

C=85°

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