in triangle abc the points D and P are on line a b and the points p and q are on line AC such that d e parallel PQ parallel BC if ad is to DP is to B E is equals 1 is to 2 is to 3 then AE is to EQ is to QC equals
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Your question is wrong the correct question is
In triangle abc the points D and P are on line a b and the points e and q are on line AC such that d e parallel PQ parallel BC if ad is to DP is to B E is equals 1 is to 2 is to 3 then AE is to EQ is to QC equals
Now AD:DP:BE=1:2:3
So,AD:DP=1:2
&
DP:PB=2:3
AD+DP:PB=3:3
→AP:PB=3:3
Now ∆ADE ≈APQ
So,AD:DP=AE:EQ
→AE=EQ=1:2----------(1)
Also
∆APQ≈∆ABC
So,
AP:PB=AQ:QC
→AQ:QC=3:3
→AE+EQ:QC=3:3
→1+EQ:QC=1+2:3
→EQ:QC=2:3---------(2)
From (1) & (2) we get
AE:EQ:QC=1:2:3
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In a triangle all sides are equal
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