in triangle ABC the sides AB and AC are equal .Also BC = 6cm and angle B 37 degree . Find the altitude through A
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Answer:
Here altitude from A to BC is AD, we know in isosceles altitude on non equal sides also median,
so, BD=CD=
2
BC
=
214=7cm
Now, we applying Pythagoras theorem in △ABD,
AB
2
=BD 2 +AD
2(25)
2 =(7) 2 +AD 2AD 2
=625−49
AD 2 =576
AD=24cm
∴ Altitude from A to BC=AD=24cm
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