In Triangle ABC the sides AB and AC are equal . If P is a point on AB and Q is a point on AC such that AP= AQ Prove that Trianglr APC and Tiangle AQB are congruent
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REF. Image.
Given AB=AC
and AP=AQ
Thus
AB-AP=AC-AQ
[BP=CA ] [from figure ]
now InΔBCP & ΔBCQ
BP = CQ
∠c=∠c [common]
and BC=BC [common]
∴ΔBCP≃ΔBCQ [SAS congruency]
now
[BQ=CP] [corresponding parts of congruent triangles]
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