In triangle ABC, the value of sin c+a/2 is:
a) 1/root2
b) root3/2
c) sin b/2
d) cos b/2
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Hy!
In ∆ABC
a+b+c=180
c+a=180-b
dividing by 2 on both sides
c+a/2=90-b/2
taking sin on both sides
sin c+a/2=sin(90-b/2)= cos b/2
option d) is correct!
Hope it helps
In ∆ABC
a+b+c=180
c+a=180-b
dividing by 2 on both sides
c+a/2=90-b/2
taking sin on both sides
sin c+a/2=sin(90-b/2)= cos b/2
option d) is correct!
Hope it helps
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