In triangle ABC, the vertex A is (5, -1) and the midpoint of BC is (-2, 3). Find the centroid.
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an important property of the centroid is that it is located 2/3rd of the distance from the vertex.
so we can say that the centroid divides the median in the ratio 2:1
apply section formula x=m1x2+m2x1/m1+m2
similarly for y too
y=m1y2+m2y1/m1+m2
solve by substituting the coordinates of the vertex and midpoint(m1 and m2 is the ratio of division)
therefore centroid will be (1/3, 5/3)
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